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How to make rectangular flow chart?
The Next CEO of Stack OverflowDrawing a database flowchart in LatexHow to draw an arrow next to the rectangle?tikz: how to create a swimlane diagram in tikzHow to define the default vertical distance between nodes?Drawing flow diagram in LaTeX using TikZNumerical conditional within tikz keys?TikZ: Drawing an arc from an intersection to an intersectionDrawing rectilinear curves in Tikz, aka an Etch-a-Sketch drawingLine up nested tikz enviroments or how to get rid of themFlow chart with coordinate system at specific nodeHow to make this array with link-list?How to draw molecular excitation by light diagramHow to draw an arrow next to the rectangle?
I am facing problems with the following diagram given into image:
How may I code for it in overleaf code? by using tikz package
begintikzpicture
draw[black, thick] (0,0) rectangle (3,2) node[pos=.5] text;
endtikzpicture
tikz-pgf
add a comment |
I am facing problems with the following diagram given into image:
How may I code for it in overleaf code? by using tikz package
begintikzpicture
draw[black, thick] (0,0) rectangle (3,2) node[pos=.5] text;
endtikzpicture
tikz-pgf
Maybe some starting point: tex.stackexchange.com/questions/350513/…
– samcarter
11 hours ago
ok, thank you very much.
– SANJAY GUPTA
11 hours ago
The next time you can probably edit your previous question in place to create a new one that is an "edit" of the first one ;)
– Kpym
10 hours ago
add a comment |
I am facing problems with the following diagram given into image:
How may I code for it in overleaf code? by using tikz package
begintikzpicture
draw[black, thick] (0,0) rectangle (3,2) node[pos=.5] text;
endtikzpicture
tikz-pgf
I am facing problems with the following diagram given into image:
How may I code for it in overleaf code? by using tikz package
begintikzpicture
draw[black, thick] (0,0) rectangle (3,2) node[pos=.5] text;
endtikzpicture
tikz-pgf
tikz-pgf
edited 4 hours ago
LianTze Lim
8,69323066
8,69323066
asked 12 hours ago
SANJAY GUPTASANJAY GUPTA
232
232
Maybe some starting point: tex.stackexchange.com/questions/350513/…
– samcarter
11 hours ago
ok, thank you very much.
– SANJAY GUPTA
11 hours ago
The next time you can probably edit your previous question in place to create a new one that is an "edit" of the first one ;)
– Kpym
10 hours ago
add a comment |
Maybe some starting point: tex.stackexchange.com/questions/350513/…
– samcarter
11 hours ago
ok, thank you very much.
– SANJAY GUPTA
11 hours ago
The next time you can probably edit your previous question in place to create a new one that is an "edit" of the first one ;)
– Kpym
10 hours ago
Maybe some starting point: tex.stackexchange.com/questions/350513/…
– samcarter
11 hours ago
Maybe some starting point: tex.stackexchange.com/questions/350513/…
– samcarter
11 hours ago
ok, thank you very much.
– SANJAY GUPTA
11 hours ago
ok, thank you very much.
– SANJAY GUPTA
11 hours ago
The next time you can probably edit your previous question in place to create a new one that is an "edit" of the first one ;)
– Kpym
10 hours ago
The next time you can probably edit your previous question in place to create a new one that is an "edit" of the first one ;)
– Kpym
10 hours ago
add a comment |
1 Answer
1
active
oldest
votes
This is to give you a start. For each of the features you will find many posts on this site, perhaps not yet in precisely this combination.
documentclass[border=3.14mm,tikz]standalone
usetikzlibrarychains,positioning,calc,shapes.geometric
begindocument
begintikzpicture[font=sffamily,boxed/.style=minimum width=3cm,minimum height=2cm,draw,thick]
beginscope[local bounding box=upper]
beginscope[start chain=1 going below,every join/.style=-latex,thick,frm/.style=boxed,on chain=1,join]
node[on chain=1](n0) Training data set;
node[frm](n1) abc;
node[frm](n2) abc;
node[frm](n3) abc;
node[frm](n4) abc;
endscope
node[boxed,right=3cm of n1] (n5) abc;
node[boxed,right=3mm of n2] (n6) abc;
node at (n0-|n6) (n7) Testing data set;
node[boxed,right=1cm of n3] (n8) abc;
endscope
draw let p1=($(upper.east)-(upper.west)$) in
node[boxed,below=5mm of upper,minimum width=x1] (n9) abc;
node[below=3mm of n9,
trapezium,trapezium left angle=60,trapezium right angle=120,
minimum width=3cm,minimum height=1cm,draw,thick] (n10) abc;
beginscope[every edge/.style=draw,-latex,thick]
path (n7) edge (n6) (n6.-140) edge (n9.north-|n6.-140)
(n1) edge (n5) (n5) edge (n9.north-|n5.south)
(n6.south-|n8) edge (n8) (n8) edge (n9.north-|n8.south)
(n4) edge (n9.north-|n4) (n9) edge (n10);
endscope
endtikzpicture
enddocument
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
This is to give you a start. For each of the features you will find many posts on this site, perhaps not yet in precisely this combination.
documentclass[border=3.14mm,tikz]standalone
usetikzlibrarychains,positioning,calc,shapes.geometric
begindocument
begintikzpicture[font=sffamily,boxed/.style=minimum width=3cm,minimum height=2cm,draw,thick]
beginscope[local bounding box=upper]
beginscope[start chain=1 going below,every join/.style=-latex,thick,frm/.style=boxed,on chain=1,join]
node[on chain=1](n0) Training data set;
node[frm](n1) abc;
node[frm](n2) abc;
node[frm](n3) abc;
node[frm](n4) abc;
endscope
node[boxed,right=3cm of n1] (n5) abc;
node[boxed,right=3mm of n2] (n6) abc;
node at (n0-|n6) (n7) Testing data set;
node[boxed,right=1cm of n3] (n8) abc;
endscope
draw let p1=($(upper.east)-(upper.west)$) in
node[boxed,below=5mm of upper,minimum width=x1] (n9) abc;
node[below=3mm of n9,
trapezium,trapezium left angle=60,trapezium right angle=120,
minimum width=3cm,minimum height=1cm,draw,thick] (n10) abc;
beginscope[every edge/.style=draw,-latex,thick]
path (n7) edge (n6) (n6.-140) edge (n9.north-|n6.-140)
(n1) edge (n5) (n5) edge (n9.north-|n5.south)
(n6.south-|n8) edge (n8) (n8) edge (n9.north-|n8.south)
(n4) edge (n9.north-|n4) (n9) edge (n10);
endscope
endtikzpicture
enddocument
add a comment |
This is to give you a start. For each of the features you will find many posts on this site, perhaps not yet in precisely this combination.
documentclass[border=3.14mm,tikz]standalone
usetikzlibrarychains,positioning,calc,shapes.geometric
begindocument
begintikzpicture[font=sffamily,boxed/.style=minimum width=3cm,minimum height=2cm,draw,thick]
beginscope[local bounding box=upper]
beginscope[start chain=1 going below,every join/.style=-latex,thick,frm/.style=boxed,on chain=1,join]
node[on chain=1](n0) Training data set;
node[frm](n1) abc;
node[frm](n2) abc;
node[frm](n3) abc;
node[frm](n4) abc;
endscope
node[boxed,right=3cm of n1] (n5) abc;
node[boxed,right=3mm of n2] (n6) abc;
node at (n0-|n6) (n7) Testing data set;
node[boxed,right=1cm of n3] (n8) abc;
endscope
draw let p1=($(upper.east)-(upper.west)$) in
node[boxed,below=5mm of upper,minimum width=x1] (n9) abc;
node[below=3mm of n9,
trapezium,trapezium left angle=60,trapezium right angle=120,
minimum width=3cm,minimum height=1cm,draw,thick] (n10) abc;
beginscope[every edge/.style=draw,-latex,thick]
path (n7) edge (n6) (n6.-140) edge (n9.north-|n6.-140)
(n1) edge (n5) (n5) edge (n9.north-|n5.south)
(n6.south-|n8) edge (n8) (n8) edge (n9.north-|n8.south)
(n4) edge (n9.north-|n4) (n9) edge (n10);
endscope
endtikzpicture
enddocument
add a comment |
This is to give you a start. For each of the features you will find many posts on this site, perhaps not yet in precisely this combination.
documentclass[border=3.14mm,tikz]standalone
usetikzlibrarychains,positioning,calc,shapes.geometric
begindocument
begintikzpicture[font=sffamily,boxed/.style=minimum width=3cm,minimum height=2cm,draw,thick]
beginscope[local bounding box=upper]
beginscope[start chain=1 going below,every join/.style=-latex,thick,frm/.style=boxed,on chain=1,join]
node[on chain=1](n0) Training data set;
node[frm](n1) abc;
node[frm](n2) abc;
node[frm](n3) abc;
node[frm](n4) abc;
endscope
node[boxed,right=3cm of n1] (n5) abc;
node[boxed,right=3mm of n2] (n6) abc;
node at (n0-|n6) (n7) Testing data set;
node[boxed,right=1cm of n3] (n8) abc;
endscope
draw let p1=($(upper.east)-(upper.west)$) in
node[boxed,below=5mm of upper,minimum width=x1] (n9) abc;
node[below=3mm of n9,
trapezium,trapezium left angle=60,trapezium right angle=120,
minimum width=3cm,minimum height=1cm,draw,thick] (n10) abc;
beginscope[every edge/.style=draw,-latex,thick]
path (n7) edge (n6) (n6.-140) edge (n9.north-|n6.-140)
(n1) edge (n5) (n5) edge (n9.north-|n5.south)
(n6.south-|n8) edge (n8) (n8) edge (n9.north-|n8.south)
(n4) edge (n9.north-|n4) (n9) edge (n10);
endscope
endtikzpicture
enddocument
This is to give you a start. For each of the features you will find many posts on this site, perhaps not yet in precisely this combination.
documentclass[border=3.14mm,tikz]standalone
usetikzlibrarychains,positioning,calc,shapes.geometric
begindocument
begintikzpicture[font=sffamily,boxed/.style=minimum width=3cm,minimum height=2cm,draw,thick]
beginscope[local bounding box=upper]
beginscope[start chain=1 going below,every join/.style=-latex,thick,frm/.style=boxed,on chain=1,join]
node[on chain=1](n0) Training data set;
node[frm](n1) abc;
node[frm](n2) abc;
node[frm](n3) abc;
node[frm](n4) abc;
endscope
node[boxed,right=3cm of n1] (n5) abc;
node[boxed,right=3mm of n2] (n6) abc;
node at (n0-|n6) (n7) Testing data set;
node[boxed,right=1cm of n3] (n8) abc;
endscope
draw let p1=($(upper.east)-(upper.west)$) in
node[boxed,below=5mm of upper,minimum width=x1] (n9) abc;
node[below=3mm of n9,
trapezium,trapezium left angle=60,trapezium right angle=120,
minimum width=3cm,minimum height=1cm,draw,thick] (n10) abc;
beginscope[every edge/.style=draw,-latex,thick]
path (n7) edge (n6) (n6.-140) edge (n9.north-|n6.-140)
(n1) edge (n5) (n5) edge (n9.north-|n5.south)
(n6.south-|n8) edge (n8) (n8) edge (n9.north-|n8.south)
(n4) edge (n9.north-|n4) (n9) edge (n10);
endscope
endtikzpicture
enddocument
answered 11 hours ago
marmotmarmot
112k5144271
112k5144271
add a comment |
add a comment |
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Maybe some starting point: tex.stackexchange.com/questions/350513/…
– samcarter
11 hours ago
ok, thank you very much.
– SANJAY GUPTA
11 hours ago
The next time you can probably edit your previous question in place to create a new one that is an "edit" of the first one ;)
– Kpym
10 hours ago