Measuring resistivity of dielectric liquid The Next CEO of Stack OverflowBoundary Conditions for dielectric-conductor interfaceHow can cellphones be charged and used at the same time?Measuring voltage across short circuitUsing OR controller TPS2115ACapacitor effects
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Measuring resistivity of dielectric liquid
The Next CEO of Stack OverflowBoundary Conditions for dielectric-conductor interfaceHow can cellphones be charged and used at the same time?Measuring voltage across short circuitUsing OR controller TPS2115ACapacitor effects
$begingroup$
Is it possible to reliably determine the resistivity of a highly resistive liquid above the breakdown voltage (i.e. after ionising the substance)?
electricity
$endgroup$
add a comment |
$begingroup$
Is it possible to reliably determine the resistivity of a highly resistive liquid above the breakdown voltage (i.e. after ionising the substance)?
electricity
$endgroup$
add a comment |
$begingroup$
Is it possible to reliably determine the resistivity of a highly resistive liquid above the breakdown voltage (i.e. after ionising the substance)?
electricity
$endgroup$
Is it possible to reliably determine the resistivity of a highly resistive liquid above the breakdown voltage (i.e. after ionising the substance)?
electricity
electricity
asked 10 hours ago
J. DoeJ. Doe
506
506
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
You can determine the resistivity of anything, by measuring the voltage that causes a current to flow.
It's only useful to say that you've 'determined' the resistivity if it's reasonably linear (so stays the same as the voltage varies) and constant (is the same tomorrow as today).
The ionised fluid after a breakdown due to excessive voltage tends to have a conductivity that varies over many orders of magnitude, determined by the power that's being dissipated in it, the output impedance of the power source, and any impurities in it. It is very, very non-constant, and non-linear. Any breakdown may release material from the electrodes, changing the impurity level.
$endgroup$
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You can determine the resistivity of anything, by measuring the voltage that causes a current to flow.
It's only useful to say that you've 'determined' the resistivity if it's reasonably linear (so stays the same as the voltage varies) and constant (is the same tomorrow as today).
The ionised fluid after a breakdown due to excessive voltage tends to have a conductivity that varies over many orders of magnitude, determined by the power that's being dissipated in it, the output impedance of the power source, and any impurities in it. It is very, very non-constant, and non-linear. Any breakdown may release material from the electrodes, changing the impurity level.
$endgroup$
add a comment |
$begingroup$
You can determine the resistivity of anything, by measuring the voltage that causes a current to flow.
It's only useful to say that you've 'determined' the resistivity if it's reasonably linear (so stays the same as the voltage varies) and constant (is the same tomorrow as today).
The ionised fluid after a breakdown due to excessive voltage tends to have a conductivity that varies over many orders of magnitude, determined by the power that's being dissipated in it, the output impedance of the power source, and any impurities in it. It is very, very non-constant, and non-linear. Any breakdown may release material from the electrodes, changing the impurity level.
$endgroup$
add a comment |
$begingroup$
You can determine the resistivity of anything, by measuring the voltage that causes a current to flow.
It's only useful to say that you've 'determined' the resistivity if it's reasonably linear (so stays the same as the voltage varies) and constant (is the same tomorrow as today).
The ionised fluid after a breakdown due to excessive voltage tends to have a conductivity that varies over many orders of magnitude, determined by the power that's being dissipated in it, the output impedance of the power source, and any impurities in it. It is very, very non-constant, and non-linear. Any breakdown may release material from the electrodes, changing the impurity level.
$endgroup$
You can determine the resistivity of anything, by measuring the voltage that causes a current to flow.
It's only useful to say that you've 'determined' the resistivity if it's reasonably linear (so stays the same as the voltage varies) and constant (is the same tomorrow as today).
The ionised fluid after a breakdown due to excessive voltage tends to have a conductivity that varies over many orders of magnitude, determined by the power that's being dissipated in it, the output impedance of the power source, and any impurities in it. It is very, very non-constant, and non-linear. Any breakdown may release material from the electrodes, changing the impurity level.
answered 10 hours ago
Neil_UKNeil_UK
78.2k284181
78.2k284181
add a comment |
add a comment |
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