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How is it possible to add a double into an ArrayList of Integer? (Java)
The Next CEO of Stack OverflowJava generics type erasure: when and what happens?type erasure in implementation of ArrayList in JavaHow do I efficiently iterate over each entry in a Java Map?How do I call one constructor from another in Java?How do I read / convert an InputStream into a String in Java?When to use LinkedList over ArrayList in Java?How do I generate random integers within a specific range in Java?How do I determine whether an array contains a particular value in Java?How do I declare and initialize an array in Java?How to split a string in JavaConverting 'ArrayList<String> to 'String[]' in JavaHow do I convert a String to an int in Java?
I try to understand how is it possible to have a Double value into an ArrayList of Integer. The numList is an ArrayList of Integer, and the value from it is a Double.
This is the code:
package bounded.wildcards;
import java.util.ArrayList;
import java.util.List;
public class GenericsDemo
public static void main(String[] args)
// Invariance Workaround
List<Integer> numList = new ArrayList<>();
GenericsDemo.invarianceWorkaround(numList);
System.out.println(numList);
static <T extends Number> void invarianceWorkaround(List<T> list)
T element = (T) new Double(23.3);
list.add(element);
This will compile and run without an error.
java generics arraylist
add a comment |
I try to understand how is it possible to have a Double value into an ArrayList of Integer. The numList is an ArrayList of Integer, and the value from it is a Double.
This is the code:
package bounded.wildcards;
import java.util.ArrayList;
import java.util.List;
public class GenericsDemo
public static void main(String[] args)
// Invariance Workaround
List<Integer> numList = new ArrayList<>();
GenericsDemo.invarianceWorkaround(numList);
System.out.println(numList);
static <T extends Number> void invarianceWorkaround(List<T> list)
T element = (T) new Double(23.3);
list.add(element);
This will compile and run without an error.
java generics arraylist
2
Possible duplicate of type erasure in implementation of ArrayList in Java
– vaxquis
11 hours ago
1
also, stackoverflow.com/questions/339699/… and many others... I think that someone can find an exact duplicate, but they are are extremely closely related.
– vaxquis
11 hours ago
Thank you for the links, I know about type erasure and add cast, but I cannot understand how is it possible to have an ArrayList of Integer with this Double value in it. And there is no exception when I run it.
– gaby
5 hours ago
@gabv you're contradicting yourself. If you knew about type erasure, you'd understand why you can add anything toArrayList<Double>at runtime... because the answer is because of type erasure. As such, it follows you must either not know about type erasure mechanism in Java or not understand it, which both mean you should learn more about it.
– vaxquis
3 hours ago
add a comment |
I try to understand how is it possible to have a Double value into an ArrayList of Integer. The numList is an ArrayList of Integer, and the value from it is a Double.
This is the code:
package bounded.wildcards;
import java.util.ArrayList;
import java.util.List;
public class GenericsDemo
public static void main(String[] args)
// Invariance Workaround
List<Integer> numList = new ArrayList<>();
GenericsDemo.invarianceWorkaround(numList);
System.out.println(numList);
static <T extends Number> void invarianceWorkaround(List<T> list)
T element = (T) new Double(23.3);
list.add(element);
This will compile and run without an error.
java generics arraylist
I try to understand how is it possible to have a Double value into an ArrayList of Integer. The numList is an ArrayList of Integer, and the value from it is a Double.
This is the code:
package bounded.wildcards;
import java.util.ArrayList;
import java.util.List;
public class GenericsDemo
public static void main(String[] args)
// Invariance Workaround
List<Integer> numList = new ArrayList<>();
GenericsDemo.invarianceWorkaround(numList);
System.out.println(numList);
static <T extends Number> void invarianceWorkaround(List<T> list)
T element = (T) new Double(23.3);
list.add(element);
This will compile and run without an error.
java generics arraylist
java generics arraylist
edited 11 hours ago
gaby
asked 12 hours ago
gabygaby
51412
51412
2
Possible duplicate of type erasure in implementation of ArrayList in Java
– vaxquis
11 hours ago
1
also, stackoverflow.com/questions/339699/… and many others... I think that someone can find an exact duplicate, but they are are extremely closely related.
– vaxquis
11 hours ago
Thank you for the links, I know about type erasure and add cast, but I cannot understand how is it possible to have an ArrayList of Integer with this Double value in it. And there is no exception when I run it.
– gaby
5 hours ago
@gabv you're contradicting yourself. If you knew about type erasure, you'd understand why you can add anything toArrayList<Double>at runtime... because the answer is because of type erasure. As such, it follows you must either not know about type erasure mechanism in Java or not understand it, which both mean you should learn more about it.
– vaxquis
3 hours ago
add a comment |
2
Possible duplicate of type erasure in implementation of ArrayList in Java
– vaxquis
11 hours ago
1
also, stackoverflow.com/questions/339699/… and many others... I think that someone can find an exact duplicate, but they are are extremely closely related.
– vaxquis
11 hours ago
Thank you for the links, I know about type erasure and add cast, but I cannot understand how is it possible to have an ArrayList of Integer with this Double value in it. And there is no exception when I run it.
– gaby
5 hours ago
@gabv you're contradicting yourself. If you knew about type erasure, you'd understand why you can add anything toArrayList<Double>at runtime... because the answer is because of type erasure. As such, it follows you must either not know about type erasure mechanism in Java or not understand it, which both mean you should learn more about it.
– vaxquis
3 hours ago
2
2
Possible duplicate of type erasure in implementation of ArrayList in Java
– vaxquis
11 hours ago
Possible duplicate of type erasure in implementation of ArrayList in Java
– vaxquis
11 hours ago
1
1
also, stackoverflow.com/questions/339699/… and many others... I think that someone can find an exact duplicate, but they are are extremely closely related.
– vaxquis
11 hours ago
also, stackoverflow.com/questions/339699/… and many others... I think that someone can find an exact duplicate, but they are are extremely closely related.
– vaxquis
11 hours ago
Thank you for the links, I know about type erasure and add cast, but I cannot understand how is it possible to have an ArrayList of Integer with this Double value in it. And there is no exception when I run it.
– gaby
5 hours ago
Thank you for the links, I know about type erasure and add cast, but I cannot understand how is it possible to have an ArrayList of Integer with this Double value in it. And there is no exception when I run it.
– gaby
5 hours ago
@gabv you're contradicting yourself. If you knew about type erasure, you'd understand why you can add anything to
ArrayList<Double> at runtime... because the answer is because of type erasure. As such, it follows you must either not know about type erasure mechanism in Java or not understand it, which both mean you should learn more about it.– vaxquis
3 hours ago
@gabv you're contradicting yourself. If you knew about type erasure, you'd understand why you can add anything to
ArrayList<Double> at runtime... because the answer is because of type erasure. As such, it follows you must either not know about type erasure mechanism in Java or not understand it, which both mean you should learn more about it.– vaxquis
3 hours ago
add a comment |
1 Answer
1
active
oldest
votes
This is because of type erasure used with Java generics - the type checks are only performed at compile time for generic types, and the type info for generics is then erased, effectively turning List<Integer> into List<Object>.
My IDE warns you of an "Unchecked cast from Double to T". But the compiler couldn't be sure that your code is wrong, so it does not emit an error, just a warning.
Then at runtime, the type check is no longer present due to type erasure, so the code will run without error unless you perform some operation that fails due to incompatible runtime type. System.out.println() is not such operation.
If you change the print code to
Integer num = numList.get(0);
System.out.println(num);
this will now involve runtime type check and will therefore fail:
java.lang.ClassCastException: java.lang.Double cannot be cast to java.lang.Integer
3
Note that aClassCastExceptionis emitted when one tries to do this:Integer i = numList.get(0).
– MC Emperor
12 hours ago
@MCEmperor Thanks, added. I couldn't find a simple example to force type incompatibility - integer seems to basically have no meaningful methods that wouldn't either be static or already inNumber.
– Jiri Tousek
12 hours ago
2
@JiriTousek You may be interested in Java is Unsound. Basically all java compilers will add cast checks in places to avoid issues because they know that the type system is broken.
– Giacomo Alzetta
11 hours ago
effectively turning intoList<Number>notList<Object>because of upper bound isNumber. if its List<Object> then you can store String but you can't
– Akash Shah
11 hours ago
@AkashShah I disagree:List<String> stringList = (List) numList; stringList.add("abc");. Lots of compiler warnings, but compiles and runs nevertheless.
– Jiri Tousek
1 hour ago
|
show 1 more comment
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1 Answer
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votes
active
oldest
votes
This is because of type erasure used with Java generics - the type checks are only performed at compile time for generic types, and the type info for generics is then erased, effectively turning List<Integer> into List<Object>.
My IDE warns you of an "Unchecked cast from Double to T". But the compiler couldn't be sure that your code is wrong, so it does not emit an error, just a warning.
Then at runtime, the type check is no longer present due to type erasure, so the code will run without error unless you perform some operation that fails due to incompatible runtime type. System.out.println() is not such operation.
If you change the print code to
Integer num = numList.get(0);
System.out.println(num);
this will now involve runtime type check and will therefore fail:
java.lang.ClassCastException: java.lang.Double cannot be cast to java.lang.Integer
3
Note that aClassCastExceptionis emitted when one tries to do this:Integer i = numList.get(0).
– MC Emperor
12 hours ago
@MCEmperor Thanks, added. I couldn't find a simple example to force type incompatibility - integer seems to basically have no meaningful methods that wouldn't either be static or already inNumber.
– Jiri Tousek
12 hours ago
2
@JiriTousek You may be interested in Java is Unsound. Basically all java compilers will add cast checks in places to avoid issues because they know that the type system is broken.
– Giacomo Alzetta
11 hours ago
effectively turning intoList<Number>notList<Object>because of upper bound isNumber. if its List<Object> then you can store String but you can't
– Akash Shah
11 hours ago
@AkashShah I disagree:List<String> stringList = (List) numList; stringList.add("abc");. Lots of compiler warnings, but compiles and runs nevertheless.
– Jiri Tousek
1 hour ago
|
show 1 more comment
This is because of type erasure used with Java generics - the type checks are only performed at compile time for generic types, and the type info for generics is then erased, effectively turning List<Integer> into List<Object>.
My IDE warns you of an "Unchecked cast from Double to T". But the compiler couldn't be sure that your code is wrong, so it does not emit an error, just a warning.
Then at runtime, the type check is no longer present due to type erasure, so the code will run without error unless you perform some operation that fails due to incompatible runtime type. System.out.println() is not such operation.
If you change the print code to
Integer num = numList.get(0);
System.out.println(num);
this will now involve runtime type check and will therefore fail:
java.lang.ClassCastException: java.lang.Double cannot be cast to java.lang.Integer
3
Note that aClassCastExceptionis emitted when one tries to do this:Integer i = numList.get(0).
– MC Emperor
12 hours ago
@MCEmperor Thanks, added. I couldn't find a simple example to force type incompatibility - integer seems to basically have no meaningful methods that wouldn't either be static or already inNumber.
– Jiri Tousek
12 hours ago
2
@JiriTousek You may be interested in Java is Unsound. Basically all java compilers will add cast checks in places to avoid issues because they know that the type system is broken.
– Giacomo Alzetta
11 hours ago
effectively turning intoList<Number>notList<Object>because of upper bound isNumber. if its List<Object> then you can store String but you can't
– Akash Shah
11 hours ago
@AkashShah I disagree:List<String> stringList = (List) numList; stringList.add("abc");. Lots of compiler warnings, but compiles and runs nevertheless.
– Jiri Tousek
1 hour ago
|
show 1 more comment
This is because of type erasure used with Java generics - the type checks are only performed at compile time for generic types, and the type info for generics is then erased, effectively turning List<Integer> into List<Object>.
My IDE warns you of an "Unchecked cast from Double to T". But the compiler couldn't be sure that your code is wrong, so it does not emit an error, just a warning.
Then at runtime, the type check is no longer present due to type erasure, so the code will run without error unless you perform some operation that fails due to incompatible runtime type. System.out.println() is not such operation.
If you change the print code to
Integer num = numList.get(0);
System.out.println(num);
this will now involve runtime type check and will therefore fail:
java.lang.ClassCastException: java.lang.Double cannot be cast to java.lang.Integer
This is because of type erasure used with Java generics - the type checks are only performed at compile time for generic types, and the type info for generics is then erased, effectively turning List<Integer> into List<Object>.
My IDE warns you of an "Unchecked cast from Double to T". But the compiler couldn't be sure that your code is wrong, so it does not emit an error, just a warning.
Then at runtime, the type check is no longer present due to type erasure, so the code will run without error unless you perform some operation that fails due to incompatible runtime type. System.out.println() is not such operation.
If you change the print code to
Integer num = numList.get(0);
System.out.println(num);
this will now involve runtime type check and will therefore fail:
java.lang.ClassCastException: java.lang.Double cannot be cast to java.lang.Integer
edited 12 hours ago
answered 12 hours ago
Jiri TousekJiri Tousek
10.5k52240
10.5k52240
3
Note that aClassCastExceptionis emitted when one tries to do this:Integer i = numList.get(0).
– MC Emperor
12 hours ago
@MCEmperor Thanks, added. I couldn't find a simple example to force type incompatibility - integer seems to basically have no meaningful methods that wouldn't either be static or already inNumber.
– Jiri Tousek
12 hours ago
2
@JiriTousek You may be interested in Java is Unsound. Basically all java compilers will add cast checks in places to avoid issues because they know that the type system is broken.
– Giacomo Alzetta
11 hours ago
effectively turning intoList<Number>notList<Object>because of upper bound isNumber. if its List<Object> then you can store String but you can't
– Akash Shah
11 hours ago
@AkashShah I disagree:List<String> stringList = (List) numList; stringList.add("abc");. Lots of compiler warnings, but compiles and runs nevertheless.
– Jiri Tousek
1 hour ago
|
show 1 more comment
3
Note that aClassCastExceptionis emitted when one tries to do this:Integer i = numList.get(0).
– MC Emperor
12 hours ago
@MCEmperor Thanks, added. I couldn't find a simple example to force type incompatibility - integer seems to basically have no meaningful methods that wouldn't either be static or already inNumber.
– Jiri Tousek
12 hours ago
2
@JiriTousek You may be interested in Java is Unsound. Basically all java compilers will add cast checks in places to avoid issues because they know that the type system is broken.
– Giacomo Alzetta
11 hours ago
effectively turning intoList<Number>notList<Object>because of upper bound isNumber. if its List<Object> then you can store String but you can't
– Akash Shah
11 hours ago
@AkashShah I disagree:List<String> stringList = (List) numList; stringList.add("abc");. Lots of compiler warnings, but compiles and runs nevertheless.
– Jiri Tousek
1 hour ago
3
3
Note that a
ClassCastException is emitted when one tries to do this: Integer i = numList.get(0).– MC Emperor
12 hours ago
Note that a
ClassCastException is emitted when one tries to do this: Integer i = numList.get(0).– MC Emperor
12 hours ago
@MCEmperor Thanks, added. I couldn't find a simple example to force type incompatibility - integer seems to basically have no meaningful methods that wouldn't either be static or already in
Number.– Jiri Tousek
12 hours ago
@MCEmperor Thanks, added. I couldn't find a simple example to force type incompatibility - integer seems to basically have no meaningful methods that wouldn't either be static or already in
Number.– Jiri Tousek
12 hours ago
2
2
@JiriTousek You may be interested in Java is Unsound. Basically all java compilers will add cast checks in places to avoid issues because they know that the type system is broken.
– Giacomo Alzetta
11 hours ago
@JiriTousek You may be interested in Java is Unsound. Basically all java compilers will add cast checks in places to avoid issues because they know that the type system is broken.
– Giacomo Alzetta
11 hours ago
effectively turning into
List<Number> not List<Object> because of upper bound is Number. if its List<Object> then you can store String but you can't– Akash Shah
11 hours ago
effectively turning into
List<Number> not List<Object> because of upper bound is Number. if its List<Object> then you can store String but you can't– Akash Shah
11 hours ago
@AkashShah I disagree:
List<String> stringList = (List) numList; stringList.add("abc");. Lots of compiler warnings, but compiles and runs nevertheless.– Jiri Tousek
1 hour ago
@AkashShah I disagree:
List<String> stringList = (List) numList; stringList.add("abc");. Lots of compiler warnings, but compiles and runs nevertheless.– Jiri Tousek
1 hour ago
|
show 1 more comment
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2
Possible duplicate of type erasure in implementation of ArrayList in Java
– vaxquis
11 hours ago
1
also, stackoverflow.com/questions/339699/… and many others... I think that someone can find an exact duplicate, but they are are extremely closely related.
– vaxquis
11 hours ago
Thank you for the links, I know about type erasure and add cast, but I cannot understand how is it possible to have an ArrayList of Integer with this Double value in it. And there is no exception when I run it.
– gaby
5 hours ago
@gabv you're contradicting yourself. If you knew about type erasure, you'd understand why you can add anything to
ArrayList<Double>at runtime... because the answer is because of type erasure. As such, it follows you must either not know about type erasure mechanism in Java or not understand it, which both mean you should learn more about it.– vaxquis
3 hours ago