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Animating planes passing through two given points in a cube
The Next CEO of Stack OverflowHow to color several transparent planes in a cube?Line through two points with offset in TikZCurve through a sequence of points with Metapost and TikZPerpendicular line to two-points-line given the lengthline passing through a point and extendingTikZ: Drawing an ellipse through two pointsCube with louvre planes in LaTeXDraw a lightning bolt between two given points in tikz?Ellipse through defined pointsDraw two opposing planes setting
Is there a smarter way to animate a collection of possible planes passing through 2 given points P on ABFE and Q on DCGH such that we can visually prove the point R is the common point of ABCD and PQ?

documentclass[pstricks,border=12pt,12pt]standalone
usepackagepst-eucl
begindocument
% first frame
beginpspicture[showgrid=false](-1,-3)(13,14)
pstGeonode[PosAngle=180,0,0,135,180](0,0)A(10,0)B(12,3)C(2,3)D(0,10)E
pstTranslation[PosAngle=0,0,135]AEB,C,D[F,G,H]
psline(E)(H)(G)(C)(B)(F)(E)(A)(B)
psline(F)(G)
psline[linestyle=dashed](H)(D)(C)
psline[linestyle=dashed](A)(D)
% Extra
pstGeonode[PosAngle=180,-90](1,9)P(7,-2)Q
pstTranslation[PosAngle=180,PointName=none,PointSymbol=none]EAP
pstTranslation[PointName=none,PointSymbol=none]BFQ
pstInterLL[PosAngle=-90]ABPP'X
pstInterLL[PosAngle=45]CDQQ'Y
pstTranslation[PosAngle=90]AEX,Y
pspolygon[linestyle=none,fillstyle=solid,fillcolor=yellow,opacity=0.25](X)(X')(Y')(Y)
pspolygon[linestyle=none,fillstyle=solid,fillcolor=cyan,opacity=0.25](A)(B)(C)(D)
psline[linecolor=red,linestyle=dashed](X)(Y)
psline[linecolor=red,linestyle=dashed](P)(Q)
pstInterLL[PosAngle=0]PQXYR
endpspicture
% second frame
beginpspicture[showgrid=false](-1,-3)(13,14)
pstGeonode[PosAngle=180,0,0,135,180](0,0)A(10,0)B(12,3)C(2,3)D(0,10)E
pstTranslation[PosAngle=0,0,135]AEB,C,D[F,G,H]
psline(E)(H)(G)(C)(B)(F)(E)(A)(B)
psline(F)(G)
psline[linestyle=dashed](H)(D)(C)
psline[linestyle=dashed](A)(D)
% Extra
pstGeonode[PosAngle=180,-90](1,9)P(7,-2)Q
pstTranslation[PosAngle=180,PointName=none,PointSymbol=none]EHP
pstTranslation[PointName=none,PointSymbol=none]CBQ
pstInterLL[PosAngle=-90]ABPQ'X
pstInterLL[PosAngle=45]CDQP'Y
pstInterLL[PosAngle=-90]EFPQ'X'
pstInterLL[PosAngle=45]HGQP'Y'
pspolygon[linestyle=none,fillstyle=solid,fillcolor=yellow,opacity=0.25](X)(X')(Y')(Y)
pspolygon[linestyle=none,fillstyle=solid,fillcolor=cyan,opacity=0.25](A)(B)(C)(D)
psline[linecolor=red,linestyle=dashed](X)(Y)
psline[linecolor=red,linestyle=dashed](P)(Q)
pstInterLL[PosAngle=0]PQXYR
endpspicture
enddocument
tikz-pgf diagrams pstricks asymptote metapost
add a comment |
Is there a smarter way to animate a collection of possible planes passing through 2 given points P on ABFE and Q on DCGH such that we can visually prove the point R is the common point of ABCD and PQ?

documentclass[pstricks,border=12pt,12pt]standalone
usepackagepst-eucl
begindocument
% first frame
beginpspicture[showgrid=false](-1,-3)(13,14)
pstGeonode[PosAngle=180,0,0,135,180](0,0)A(10,0)B(12,3)C(2,3)D(0,10)E
pstTranslation[PosAngle=0,0,135]AEB,C,D[F,G,H]
psline(E)(H)(G)(C)(B)(F)(E)(A)(B)
psline(F)(G)
psline[linestyle=dashed](H)(D)(C)
psline[linestyle=dashed](A)(D)
% Extra
pstGeonode[PosAngle=180,-90](1,9)P(7,-2)Q
pstTranslation[PosAngle=180,PointName=none,PointSymbol=none]EAP
pstTranslation[PointName=none,PointSymbol=none]BFQ
pstInterLL[PosAngle=-90]ABPP'X
pstInterLL[PosAngle=45]CDQQ'Y
pstTranslation[PosAngle=90]AEX,Y
pspolygon[linestyle=none,fillstyle=solid,fillcolor=yellow,opacity=0.25](X)(X')(Y')(Y)
pspolygon[linestyle=none,fillstyle=solid,fillcolor=cyan,opacity=0.25](A)(B)(C)(D)
psline[linecolor=red,linestyle=dashed](X)(Y)
psline[linecolor=red,linestyle=dashed](P)(Q)
pstInterLL[PosAngle=0]PQXYR
endpspicture
% second frame
beginpspicture[showgrid=false](-1,-3)(13,14)
pstGeonode[PosAngle=180,0,0,135,180](0,0)A(10,0)B(12,3)C(2,3)D(0,10)E
pstTranslation[PosAngle=0,0,135]AEB,C,D[F,G,H]
psline(E)(H)(G)(C)(B)(F)(E)(A)(B)
psline(F)(G)
psline[linestyle=dashed](H)(D)(C)
psline[linestyle=dashed](A)(D)
% Extra
pstGeonode[PosAngle=180,-90](1,9)P(7,-2)Q
pstTranslation[PosAngle=180,PointName=none,PointSymbol=none]EHP
pstTranslation[PointName=none,PointSymbol=none]CBQ
pstInterLL[PosAngle=-90]ABPQ'X
pstInterLL[PosAngle=45]CDQP'Y
pstInterLL[PosAngle=-90]EFPQ'X'
pstInterLL[PosAngle=45]HGQP'Y'
pspolygon[linestyle=none,fillstyle=solid,fillcolor=yellow,opacity=0.25](X)(X')(Y')(Y)
pspolygon[linestyle=none,fillstyle=solid,fillcolor=cyan,opacity=0.25](A)(B)(C)(D)
psline[linecolor=red,linestyle=dashed](X)(Y)
psline[linecolor=red,linestyle=dashed](P)(Q)
pstInterLL[PosAngle=0]PQXYR
endpspicture
enddocument
tikz-pgf diagrams pstricks asymptote metapost
add a comment |
Is there a smarter way to animate a collection of possible planes passing through 2 given points P on ABFE and Q on DCGH such that we can visually prove the point R is the common point of ABCD and PQ?

documentclass[pstricks,border=12pt,12pt]standalone
usepackagepst-eucl
begindocument
% first frame
beginpspicture[showgrid=false](-1,-3)(13,14)
pstGeonode[PosAngle=180,0,0,135,180](0,0)A(10,0)B(12,3)C(2,3)D(0,10)E
pstTranslation[PosAngle=0,0,135]AEB,C,D[F,G,H]
psline(E)(H)(G)(C)(B)(F)(E)(A)(B)
psline(F)(G)
psline[linestyle=dashed](H)(D)(C)
psline[linestyle=dashed](A)(D)
% Extra
pstGeonode[PosAngle=180,-90](1,9)P(7,-2)Q
pstTranslation[PosAngle=180,PointName=none,PointSymbol=none]EAP
pstTranslation[PointName=none,PointSymbol=none]BFQ
pstInterLL[PosAngle=-90]ABPP'X
pstInterLL[PosAngle=45]CDQQ'Y
pstTranslation[PosAngle=90]AEX,Y
pspolygon[linestyle=none,fillstyle=solid,fillcolor=yellow,opacity=0.25](X)(X')(Y')(Y)
pspolygon[linestyle=none,fillstyle=solid,fillcolor=cyan,opacity=0.25](A)(B)(C)(D)
psline[linecolor=red,linestyle=dashed](X)(Y)
psline[linecolor=red,linestyle=dashed](P)(Q)
pstInterLL[PosAngle=0]PQXYR
endpspicture
% second frame
beginpspicture[showgrid=false](-1,-3)(13,14)
pstGeonode[PosAngle=180,0,0,135,180](0,0)A(10,0)B(12,3)C(2,3)D(0,10)E
pstTranslation[PosAngle=0,0,135]AEB,C,D[F,G,H]
psline(E)(H)(G)(C)(B)(F)(E)(A)(B)
psline(F)(G)
psline[linestyle=dashed](H)(D)(C)
psline[linestyle=dashed](A)(D)
% Extra
pstGeonode[PosAngle=180,-90](1,9)P(7,-2)Q
pstTranslation[PosAngle=180,PointName=none,PointSymbol=none]EHP
pstTranslation[PointName=none,PointSymbol=none]CBQ
pstInterLL[PosAngle=-90]ABPQ'X
pstInterLL[PosAngle=45]CDQP'Y
pstInterLL[PosAngle=-90]EFPQ'X'
pstInterLL[PosAngle=45]HGQP'Y'
pspolygon[linestyle=none,fillstyle=solid,fillcolor=yellow,opacity=0.25](X)(X')(Y')(Y)
pspolygon[linestyle=none,fillstyle=solid,fillcolor=cyan,opacity=0.25](A)(B)(C)(D)
psline[linecolor=red,linestyle=dashed](X)(Y)
psline[linecolor=red,linestyle=dashed](P)(Q)
pstInterLL[PosAngle=0]PQXYR
endpspicture
enddocument
tikz-pgf diagrams pstricks asymptote metapost
Is there a smarter way to animate a collection of possible planes passing through 2 given points P on ABFE and Q on DCGH such that we can visually prove the point R is the common point of ABCD and PQ?

documentclass[pstricks,border=12pt,12pt]standalone
usepackagepst-eucl
begindocument
% first frame
beginpspicture[showgrid=false](-1,-3)(13,14)
pstGeonode[PosAngle=180,0,0,135,180](0,0)A(10,0)B(12,3)C(2,3)D(0,10)E
pstTranslation[PosAngle=0,0,135]AEB,C,D[F,G,H]
psline(E)(H)(G)(C)(B)(F)(E)(A)(B)
psline(F)(G)
psline[linestyle=dashed](H)(D)(C)
psline[linestyle=dashed](A)(D)
% Extra
pstGeonode[PosAngle=180,-90](1,9)P(7,-2)Q
pstTranslation[PosAngle=180,PointName=none,PointSymbol=none]EAP
pstTranslation[PointName=none,PointSymbol=none]BFQ
pstInterLL[PosAngle=-90]ABPP'X
pstInterLL[PosAngle=45]CDQQ'Y
pstTranslation[PosAngle=90]AEX,Y
pspolygon[linestyle=none,fillstyle=solid,fillcolor=yellow,opacity=0.25](X)(X')(Y')(Y)
pspolygon[linestyle=none,fillstyle=solid,fillcolor=cyan,opacity=0.25](A)(B)(C)(D)
psline[linecolor=red,linestyle=dashed](X)(Y)
psline[linecolor=red,linestyle=dashed](P)(Q)
pstInterLL[PosAngle=0]PQXYR
endpspicture
% second frame
beginpspicture[showgrid=false](-1,-3)(13,14)
pstGeonode[PosAngle=180,0,0,135,180](0,0)A(10,0)B(12,3)C(2,3)D(0,10)E
pstTranslation[PosAngle=0,0,135]AEB,C,D[F,G,H]
psline(E)(H)(G)(C)(B)(F)(E)(A)(B)
psline(F)(G)
psline[linestyle=dashed](H)(D)(C)
psline[linestyle=dashed](A)(D)
% Extra
pstGeonode[PosAngle=180,-90](1,9)P(7,-2)Q
pstTranslation[PosAngle=180,PointName=none,PointSymbol=none]EHP
pstTranslation[PointName=none,PointSymbol=none]CBQ
pstInterLL[PosAngle=-90]ABPQ'X
pstInterLL[PosAngle=45]CDQP'Y
pstInterLL[PosAngle=-90]EFPQ'X'
pstInterLL[PosAngle=45]HGQP'Y'
pspolygon[linestyle=none,fillstyle=solid,fillcolor=yellow,opacity=0.25](X)(X')(Y')(Y)
pspolygon[linestyle=none,fillstyle=solid,fillcolor=cyan,opacity=0.25](A)(B)(C)(D)
psline[linecolor=red,linestyle=dashed](X)(Y)
psline[linecolor=red,linestyle=dashed](P)(Q)
pstInterLL[PosAngle=0]PQXYR
endpspicture
enddocument
tikz-pgf diagrams pstricks asymptote metapost
tikz-pgf diagrams pstricks asymptote metapost
asked 7 hours ago
Artificial Hairless ArmpitArtificial Hairless Armpit
5,03711142
5,03711142
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
I may not do an animation and just use a plane with a nontrivial opacity such that one can see that the dashed red line hits the plane. My take is that you want to
visually prove the point R is the common point of ABCD and PQ
because this is what is written in the question. If that's not what the question is about, consider editing it to make it clearer. (Sorry, I have quit pstricks a while ago, but I am sure you will be able to redo this with pstricks.)
documentclass[tikz,border=3.14mm]standalone
usepackagetikz-3dplot
usetikzlibrarybackgrounds
newcountercoord
begindocument
tdplotsetmaincoords70200
begintikzpicture[tdplot_main_coords,scale=3,bullet/.style=fill,circle,inner sep=1pt]
foreach Z in -1,1
foreach Y in -1,1
foreach X in -1,1
stepcountercoord
path (Y*X,-1*Y,Z) coordinate (Alphcoord) -- ++ (0.2*Y*X,0,0)
node$Alphcoord$ ;
fill[cyan,opacity=0.5] (A) -- (B) -- (C) -- (D) -- cycle;
draw[dashed] (A) -- (D) -- (C) (D) -- (H);
draw (E) -- (F) -- (G) -- (H) -- (E) -- (A) -- (B) -- (C) -- (G) (B) -- (F);
node[bullet,label=left:$P$] (P) at (1,0,0.5);
node[bullet,label=above right:$R$] (R) at (1/3,0,-1);
draw[red,dashed,thick] (P) -- (R)
node[pos=1.5,black,bullet,label=[black]below:$Q$] (Q);
beginscope[on background layer]
draw[red,dashed,thick] (R) -- (Q);
endscope
endtikzpicture
enddocument

Where is the collection of infinitely many planes passing throughPQ?
– Artificial Hairless Armpit
6 hours ago
@ArtificialHairlessArmpit These planes are IMHO not necessary to "visually prove the point R is the common point of ABCD and PQ".
– marmot
6 hours ago
The planes are required for my question.
– Artificial Hairless Armpit
6 hours ago
@ArtificialHairlessArmpit But not for my answer. ;-) And sorry to say that, but your screen shot is confusing precisely because below R the line seems to run in front of the plane.
– marmot
6 hours ago
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I may not do an animation and just use a plane with a nontrivial opacity such that one can see that the dashed red line hits the plane. My take is that you want to
visually prove the point R is the common point of ABCD and PQ
because this is what is written in the question. If that's not what the question is about, consider editing it to make it clearer. (Sorry, I have quit pstricks a while ago, but I am sure you will be able to redo this with pstricks.)
documentclass[tikz,border=3.14mm]standalone
usepackagetikz-3dplot
usetikzlibrarybackgrounds
newcountercoord
begindocument
tdplotsetmaincoords70200
begintikzpicture[tdplot_main_coords,scale=3,bullet/.style=fill,circle,inner sep=1pt]
foreach Z in -1,1
foreach Y in -1,1
foreach X in -1,1
stepcountercoord
path (Y*X,-1*Y,Z) coordinate (Alphcoord) -- ++ (0.2*Y*X,0,0)
node$Alphcoord$ ;
fill[cyan,opacity=0.5] (A) -- (B) -- (C) -- (D) -- cycle;
draw[dashed] (A) -- (D) -- (C) (D) -- (H);
draw (E) -- (F) -- (G) -- (H) -- (E) -- (A) -- (B) -- (C) -- (G) (B) -- (F);
node[bullet,label=left:$P$] (P) at (1,0,0.5);
node[bullet,label=above right:$R$] (R) at (1/3,0,-1);
draw[red,dashed,thick] (P) -- (R)
node[pos=1.5,black,bullet,label=[black]below:$Q$] (Q);
beginscope[on background layer]
draw[red,dashed,thick] (R) -- (Q);
endscope
endtikzpicture
enddocument

Where is the collection of infinitely many planes passing throughPQ?
– Artificial Hairless Armpit
6 hours ago
@ArtificialHairlessArmpit These planes are IMHO not necessary to "visually prove the point R is the common point of ABCD and PQ".
– marmot
6 hours ago
The planes are required for my question.
– Artificial Hairless Armpit
6 hours ago
@ArtificialHairlessArmpit But not for my answer. ;-) And sorry to say that, but your screen shot is confusing precisely because below R the line seems to run in front of the plane.
– marmot
6 hours ago
add a comment |
I may not do an animation and just use a plane with a nontrivial opacity such that one can see that the dashed red line hits the plane. My take is that you want to
visually prove the point R is the common point of ABCD and PQ
because this is what is written in the question. If that's not what the question is about, consider editing it to make it clearer. (Sorry, I have quit pstricks a while ago, but I am sure you will be able to redo this with pstricks.)
documentclass[tikz,border=3.14mm]standalone
usepackagetikz-3dplot
usetikzlibrarybackgrounds
newcountercoord
begindocument
tdplotsetmaincoords70200
begintikzpicture[tdplot_main_coords,scale=3,bullet/.style=fill,circle,inner sep=1pt]
foreach Z in -1,1
foreach Y in -1,1
foreach X in -1,1
stepcountercoord
path (Y*X,-1*Y,Z) coordinate (Alphcoord) -- ++ (0.2*Y*X,0,0)
node$Alphcoord$ ;
fill[cyan,opacity=0.5] (A) -- (B) -- (C) -- (D) -- cycle;
draw[dashed] (A) -- (D) -- (C) (D) -- (H);
draw (E) -- (F) -- (G) -- (H) -- (E) -- (A) -- (B) -- (C) -- (G) (B) -- (F);
node[bullet,label=left:$P$] (P) at (1,0,0.5);
node[bullet,label=above right:$R$] (R) at (1/3,0,-1);
draw[red,dashed,thick] (P) -- (R)
node[pos=1.5,black,bullet,label=[black]below:$Q$] (Q);
beginscope[on background layer]
draw[red,dashed,thick] (R) -- (Q);
endscope
endtikzpicture
enddocument

Where is the collection of infinitely many planes passing throughPQ?
– Artificial Hairless Armpit
6 hours ago
@ArtificialHairlessArmpit These planes are IMHO not necessary to "visually prove the point R is the common point of ABCD and PQ".
– marmot
6 hours ago
The planes are required for my question.
– Artificial Hairless Armpit
6 hours ago
@ArtificialHairlessArmpit But not for my answer. ;-) And sorry to say that, but your screen shot is confusing precisely because below R the line seems to run in front of the plane.
– marmot
6 hours ago
add a comment |
I may not do an animation and just use a plane with a nontrivial opacity such that one can see that the dashed red line hits the plane. My take is that you want to
visually prove the point R is the common point of ABCD and PQ
because this is what is written in the question. If that's not what the question is about, consider editing it to make it clearer. (Sorry, I have quit pstricks a while ago, but I am sure you will be able to redo this with pstricks.)
documentclass[tikz,border=3.14mm]standalone
usepackagetikz-3dplot
usetikzlibrarybackgrounds
newcountercoord
begindocument
tdplotsetmaincoords70200
begintikzpicture[tdplot_main_coords,scale=3,bullet/.style=fill,circle,inner sep=1pt]
foreach Z in -1,1
foreach Y in -1,1
foreach X in -1,1
stepcountercoord
path (Y*X,-1*Y,Z) coordinate (Alphcoord) -- ++ (0.2*Y*X,0,0)
node$Alphcoord$ ;
fill[cyan,opacity=0.5] (A) -- (B) -- (C) -- (D) -- cycle;
draw[dashed] (A) -- (D) -- (C) (D) -- (H);
draw (E) -- (F) -- (G) -- (H) -- (E) -- (A) -- (B) -- (C) -- (G) (B) -- (F);
node[bullet,label=left:$P$] (P) at (1,0,0.5);
node[bullet,label=above right:$R$] (R) at (1/3,0,-1);
draw[red,dashed,thick] (P) -- (R)
node[pos=1.5,black,bullet,label=[black]below:$Q$] (Q);
beginscope[on background layer]
draw[red,dashed,thick] (R) -- (Q);
endscope
endtikzpicture
enddocument

I may not do an animation and just use a plane with a nontrivial opacity such that one can see that the dashed red line hits the plane. My take is that you want to
visually prove the point R is the common point of ABCD and PQ
because this is what is written in the question. If that's not what the question is about, consider editing it to make it clearer. (Sorry, I have quit pstricks a while ago, but I am sure you will be able to redo this with pstricks.)
documentclass[tikz,border=3.14mm]standalone
usepackagetikz-3dplot
usetikzlibrarybackgrounds
newcountercoord
begindocument
tdplotsetmaincoords70200
begintikzpicture[tdplot_main_coords,scale=3,bullet/.style=fill,circle,inner sep=1pt]
foreach Z in -1,1
foreach Y in -1,1
foreach X in -1,1
stepcountercoord
path (Y*X,-1*Y,Z) coordinate (Alphcoord) -- ++ (0.2*Y*X,0,0)
node$Alphcoord$ ;
fill[cyan,opacity=0.5] (A) -- (B) -- (C) -- (D) -- cycle;
draw[dashed] (A) -- (D) -- (C) (D) -- (H);
draw (E) -- (F) -- (G) -- (H) -- (E) -- (A) -- (B) -- (C) -- (G) (B) -- (F);
node[bullet,label=left:$P$] (P) at (1,0,0.5);
node[bullet,label=above right:$R$] (R) at (1/3,0,-1);
draw[red,dashed,thick] (P) -- (R)
node[pos=1.5,black,bullet,label=[black]below:$Q$] (Q);
beginscope[on background layer]
draw[red,dashed,thick] (R) -- (Q);
endscope
endtikzpicture
enddocument

edited 6 hours ago
answered 6 hours ago
marmotmarmot
113k5145274
113k5145274
Where is the collection of infinitely many planes passing throughPQ?
– Artificial Hairless Armpit
6 hours ago
@ArtificialHairlessArmpit These planes are IMHO not necessary to "visually prove the point R is the common point of ABCD and PQ".
– marmot
6 hours ago
The planes are required for my question.
– Artificial Hairless Armpit
6 hours ago
@ArtificialHairlessArmpit But not for my answer. ;-) And sorry to say that, but your screen shot is confusing precisely because below R the line seems to run in front of the plane.
– marmot
6 hours ago
add a comment |
Where is the collection of infinitely many planes passing throughPQ?
– Artificial Hairless Armpit
6 hours ago
@ArtificialHairlessArmpit These planes are IMHO not necessary to "visually prove the point R is the common point of ABCD and PQ".
– marmot
6 hours ago
The planes are required for my question.
– Artificial Hairless Armpit
6 hours ago
@ArtificialHairlessArmpit But not for my answer. ;-) And sorry to say that, but your screen shot is confusing precisely because below R the line seems to run in front of the plane.
– marmot
6 hours ago
Where is the collection of infinitely many planes passing through
PQ?– Artificial Hairless Armpit
6 hours ago
Where is the collection of infinitely many planes passing through
PQ?– Artificial Hairless Armpit
6 hours ago
@ArtificialHairlessArmpit These planes are IMHO not necessary to "visually prove the point R is the common point of ABCD and PQ".
– marmot
6 hours ago
@ArtificialHairlessArmpit These planes are IMHO not necessary to "visually prove the point R is the common point of ABCD and PQ".
– marmot
6 hours ago
The planes are required for my question.
– Artificial Hairless Armpit
6 hours ago
The planes are required for my question.
– Artificial Hairless Armpit
6 hours ago
@ArtificialHairlessArmpit But not for my answer. ;-) And sorry to say that, but your screen shot is confusing precisely because below R the line seems to run in front of the plane.
– marmot
6 hours ago
@ArtificialHairlessArmpit But not for my answer. ;-) And sorry to say that, but your screen shot is confusing precisely because below R the line seems to run in front of the plane.
– marmot
6 hours ago
add a comment |
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